Perfect Number in given range

-
#include<iostream>
#include<conio.h>
using namespace std;
int main()
{
int number1,number2;
int sum=0;
cout<<"\t\t\t\tPerfect Number";
cout<<"\nEnter lower bound : ";
cin>>number1;
cout<<"Enter upper bound : ";
cin>>number2;
cout<<"Pefect number is : ";
for(int i=number1;i<=number2;i++)
{
for(int j=1;j<i;j++)
{
if(i%j==0)
{
sum=sum+j;
}
}
if(sum==i)
cout<<i<<"\t";
sum=0;
}
getch();
return 0;
}
Output:-

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